Projectile Motion Calculator
Calculate range, max height, and flight time
Enter initial velocity and launch angle
Range = v^2 sin(2a)/g, Height = v^2 sin^2(a)/(2g)What Is Projectile Motion?
Projectile motion describes the curved path of an object launched into the air under the influence of gravity alone (ignoring air resistance). The motion combines a constant horizontal velocity with a uniformly accelerating vertical motion due to gravity. Together, they trace a parabolic path.
Galileo Galilei first analyzed projectile motion in the early 1600s, revealing that horizontal and vertical motions are independent. This insight is fundamental to ballistics, sports science, space launches, and engineering. Whether it's a basketball, a cannonball, or a spacecraft, the same equations govern the trajectory.
How to Use the Projectile Motion Calculator
- Enter the initial velocity (v₀) in meters per second.
- Enter the launch angle (θ) in degrees above the horizontal.
- Enter the initial height (h₀) if the launch point is above or below the landing level (default 0).
- Click Calculate to get range, maximum height, time of flight, and velocity components.
Formula & Explanation
Horizontal: x = v₀ cos(θ) × t
Vertical: y = h₀ + v₀ sin(θ) × t − ½gt²
Max height: H = h₀ + (v₀ sin θ)² / (2g)
Time of flight: T = [v₀ sin θ + √((v₀ sin θ)² + 2gh₀)] / g
Range: R = v₀ cos θ × T
v₀ = initial speed (m/s)
θ = launch angle (°)
g = 9.81 m/s²Maximum range for flat ground occurs at θ = 45°. Air resistance significantly reduces actual range — these formulas assume a vacuum.
Worked Examples
Soccer Ball Kick
A ball is kicked at 25 m/s at 40° on flat ground. vₓ = 25 cos(40°) = 19.15 m/s; vy₀ = 25 sin(40°) = 16.07 m/s. T = 2 × 16.07/9.81 = 3.28 s. Range = 19.15 × 3.28 = 62.8 m. Max height = 16.07²/(2 × 9.81) = 13.2 m.
Ball Dropped from a Building
A ball is thrown horizontally at 10 m/s from 45 m height (h₀ = 45 m, θ = 0°). Fall time t = √(2 × 45/9.81) = 3.03 s. Horizontal range = 10 × 3.03 = 30.3 m. Impact speed: vertical = 9.81 × 3.03 = 29.7 m/s; total = √(10² + 29.7²) = 31.3 m/s.
Artillery at 45°
A shell is fired at 300 m/s at 45°. vₓ = vy₀ = 300/√2 = 212.1 m/s. T = 2 × 212.1/9.81 = 43.3 s. Range = 212.1 × 43.3 = 9,174 m ≈ 9.2 km. Max height = 212.1²/(2 × 9.81) = 2,294 m ≈ 2.3 km.